Francis Oliver

## Answered question

2022-10-11

Find $\frac{dy}{dx}$ by implicit differentiation.
$\mathrm{tan}\left(x+y\right)=x$
So far, I got to
${\mathrm{sec}}^{2}\left(x+y\right)\left(1+\frac{dy}{dx}\right)=1$
but then im lost.. can someone please help and explain? I would really appreciate it!!

### Answer & Explanation

dkmc4175fl

Beginner2022-10-12Added 15 answers

Well, you have ${\mathrm{sec}}^{2}\left(x+y\right)\left(1+{y}^{\prime }\right)=1$, from which you get ${y}^{\prime }={\mathrm{cos}}^{2}\left(x+y\right)-1$.

Elise Kelley

Beginner2022-10-13Added 2 answers

you need to foil sec${}^{2}\left(x+y\right)\left(1+{y}^{\prime }\left(x\right)\right)=1$ and then solve for ${y}^{\prime }\left(x\right)$.
Think about sec${}^{2}\left(x+y\right)$ as one whole.
Hint: the answer will be in terms of $x$ and $y$

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?