Angel Kline

2022-10-14

How do you find dy/dx for $y+2x-3x{y}^{3}=4$

aitorarjolia

Beginner2022-10-15Added 11 answers

You must remember that y is a function of x so that to take into account this you

have to include $\frac{dy}{dx}$ when deriving any y in your function, as:

$1\frac{dy}{dx}+2-3{y}^{3}-9x{y}^{2}\frac{dy}{dx}=0$

Collecting $\frac{dy}{dx}$

$\frac{dy}{dx}=\frac{3{y}^{3}-2}{1-9x{y}^{2}}$

have to include $\frac{dy}{dx}$ when deriving any y in your function, as:

$1\frac{dy}{dx}+2-3{y}^{3}-9x{y}^{2}\frac{dy}{dx}=0$

Collecting $\frac{dy}{dx}$

$\frac{dy}{dx}=\frac{3{y}^{3}-2}{1-9x{y}^{2}}$

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