When f(x,y)=0, (dy)/(dx)=−(Differentiation of f w.r.t to x keeping y constant)/(Differentiation of f w.r.t to y keeping x constant)

Ignacio Riggs

Ignacio Riggs

Answered question

2022-10-29

For finding the derivative, d y d x of an implicit function, there is this formula,
When f ( x , y ) = 0,
d y d x = Differentiation of  f  w.r.t to  x  keeping  y  constant Differentiation of  f  w.r.t to  y  keeping  x  constant I want to understand how this method came about.
Is there a clear proof for this formula?

Answer & Explanation

broeifl

broeifl

Beginner2022-10-30Added 11 answers

It's pretty easy to show if you use partial differentials with a slightly different notation. Let's let x f represent the partial differential of f when we allow x to freely vary (i.e., when y is held constant). Note that when we allow x to freely vary, then its differential is always the same as the total differential, so it can be notated as d x. Similarly with y. So, the partial differential of f with respect to x is x f d x .

Now, let's put this to use. A total derivative is the sum of its partials. Therefore, the total derivative of f is going to be x f + y f. Since the right-hand side is a constant, its derivative will be zero. Therefore:
x f + y f = 0 x f = y f x f y f = 1
Now, what are our two partial derivatives? They are x f d x and y f d y . What happens if we put them in ratio with each other?
x f d x y f d y
Using fraction rules, we get (notice the "-1" comes from the equivalence above):
x f d x y f d y = x f d x d y y f = x f y f d y d x = 1 d y d x = d y d x
This is what we were looking for. On the left is the ratio of the two partial derivatives. On the right is the total derivative with a negative sign.

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