Test the convergences of the following series sum_(n=1)^infty (-1)^n sin n/sqrt(n)

szklanovqq

szklanovqq

Answered question

2022-11-12

Test the convergences of the following series
n = 1 ( 1 ) n sin n n

Answer & Explanation

Kalmukujobvg

Kalmukujobvg

Beginner2022-11-13Added 14 answers

Denote θ = 1 + π, a n = ( 1 ) n sin n = sin ( n θ ) and ϕ ( x ) = 1 x . Then compute
A ( x ) = 1 k x a k = Im ( 1 k x e i k θ ) = Im ( e i ( x + 1 ) θ e i θ e i θ 1 )
Which yields
| A ( x ) | | e i ( x + 1 ) θ e i θ e i θ 1 | 2 | e i θ 1 |
So x↦A(x) is bounded. Using Abel's summation formula, you may write
1 n x a n ϕ ( n ) = A ( x ) ϕ ( x ) 1 x A ( x ) ϕ ( x ) d x

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