f(x)=x^2 is continuous on [1,2] but does not assume the values 2 intermediate between the value 1 and 4. I do not understand what they mean. For me, sqrt(2) in [1,2] and f(sqrt2)=2. Also, using the the intermediate value theorem, since f is continuous on [1,2] and f(1)=1<2<4=f(2), there exists c in[1,2] such that f(c)=2. Can I get some explanation about this?

Jaiden Elliott

Jaiden Elliott

Answered question

2022-11-12

I found that f ( x ) = x 2 is continuous on [ 1 , 2 ] but does not assume the values 2 intermediate between the value 1 and 4. I do not understand what they mean. For me, 2 [ 1 , 2 ] and f ( 2 ) = 2.
Also, using the the intermediate value theorem, since f is continuous on [ 1 , 2 ] and f ( 1 ) = 1 < 2 < 4 = f ( 2 ), there exists c [ 1 , 2 ] such that f ( c ) = 2.
Can I get some explanation about this?

Answer & Explanation

embutiridsl

embutiridsl

Beginner2022-11-13Added 26 answers

Looking at the text before that series of examples, the authors specifically say:
We conclude this chapter with a collection of functions defined on a closed interval [ a , b ] Q and having values in Q .
So, we're not in R anymore.

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