find dy/dx by implicit differentiation xe^y-15x+5y=0

Ada Lloyd

Ada Lloyd

Answered question

2022-12-04

Help me to find dy/dx by implicit differentiation
x e y 15 x + 5 y = 0

Answer & Explanation

Jayda King

Jayda King

Beginner2022-12-05Added 8 answers

x e y 15 x + 5 y = 0 D i f f e r e n t i a t i n g   t h e   a b o v e   w . r . t . x . d d x ( x e y 15 x + 5 y ) = 0 d d x ( x e y ) 15 d d x ( x ) + 5 d d x ( y ) = 0 x d d x ( e y ) + e y d d x ( x ) 15 + 5 d y d x = 0 x d d y ( e y ) × d y d x + e y ( 1 ) 15 + 5 d y d x = 0 x ( e y ) d y d x + ( e y ) 15 + 5 d y d x = 0 d y d x [ x e y + 5 ] = 15 e y d y d x = 15 e y x e y + 5

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