How to find the center and radius of the circle given x^2+y^2+8x-6y=0?

Shayla Phelps

Shayla Phelps

Answered question

2023-03-13

How to find the center and radius of the circle given x 2 + y 2 + 8 x - 6 y = 0 ?

Answer & Explanation

Izabelle Riddle

Izabelle Riddle

Beginner2023-03-14Added 3 answers

We need
( a + b ) 2 = a 2 + 2 a b + b 2
( a - b ) 2 = a 2 - 2 a b + b 2
Complete the x and y squares.
x 2 + y 2 + 8 x - 6 y = 0
x 2 + 8 x + y 2 - 6 y = 0
x 2 + 8 x + ( 8 2 ) 2 + y 2 - 6 y + ( 6 2 ) 2 = ( 8 2 ) 2 + ( 6 2 ) 2
x 2 + 8 x + ( 4 ) 2 + y 2 - 6 y + ( 3 ) 2 = ( 4 ) 2 + ( 3 ) 2
( x + 4 ) 2 + ( y - 3 ) 2 = 25 = 5 2
This is the equation of a circle, center ( - 4 , 3 ) and radius = 5
graph{(x^2+y^2+8x-6y)=0 [-15.25, 13.23, -3.42, 10.82]}

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?