What are the vertices of 9 x 2 + 16 y 2 = 144 ?

Question

What are the vertices of       9          x      2        +    16          y      2        =    144  ?

dalematealreypq3a · Accepted Answer

9          x      2        +    16          y      2        =    144  Divide each term by       144    .                      9                  x          2                    144        +                  16                  y          2                    144        =          144      144      Simplify                              x          2                    16        +                            y          2                    9        =    1  The major axis is the x-axis because the largest denominator is under the             x      2       term.The vertices&#039; coordinates are as follows ...            (      ±      a      ,      0      )                   (      0      ,      ±      b      )                  a      2        =    16    →    a    =    4              b      2        =    4    →    b    =    2              (      ±      4      ,      0      )                   (      0      ,      ±      2      )

What are the vertices of 9x^2+16y^2=144?

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