Show that the area of ​triangle S <mrow class="MJX-TeXAtom-ORD"> A B

pouzdrotf

pouzdrotf

Answered question

2022-07-05

Show that the area of ​triangle S A B C = R × M N

Answer & Explanation

Amir Beck

Amir Beck

Beginner2022-07-06Added 13 answers

Step 1
First establish that M N = B H × sin A B C
(law of sines - sin ( H M B ) : B H = sin ( A B C ) : M N ).
Then,
A O C is isosceles, let O A C = O C A = β .
Then A O C = 180 2 β = 180 α γ .
where α , γ are the appropriate angles from the isosceles triangles A O B and B O C .
The perpendicular from O through AC divides the angle in two, i.e. 90 α γ , and so we arrive at A C = R × sin ( A B C ) .
Frederick Kramer

Frederick Kramer

Beginner2022-07-07Added 7 answers

Step 1
The orthocenter and the circumcenter of a triangle are isogonal conjugates, therefore
A B H = N B O = α H M B N ( c y c l i c ) B H M = M N B = 90 α B F N = 90 0 B O M N [ B M O N ] = [ B M N ] [ M N O ] = B O M N 2 = R M N 2 ( I ) M B N C B A M N M B = b a M H B = 90 ( 90 A ) M B = B H s e n ( A ) [ B M O N ] = R b a B H s e n ( A ) 2 = [ A B C ] R s e n ( A ) a = [ A B C ] 2 ( I I ) ( I ) = ( I I ) : [ A B C ] 2 = R . M N 2 [ A B C ] = R . M N

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