Cindy Noble

2022-09-07

Find the equation of the line between (8, -2) and (6,5) in slope intercept form

lascosasdeali3v

Beginner2022-09-08Added 10 answers

Here the concept of slope intercept form will be used .

The slope intercept form is used to provide the equation of the straight line in the form of

$y=mx+c$

Where m is the slope of the straight line and c is the y intercept of the straight line .

The point are $(8,-2)\text{and}(6,5)$

$m=slope=\frac{{y}_{2}-{y}_{1}}{{x}_{2}-{x}_{1}}=\frac{5-(-2)}{6-8}=\frac{5+2}{-2}=\frac{-7}{2}$

Now as slope intercept form is

$y=mx+c$

Putting m we get $y=\frac{-7n}{2}+C$

Now substituting a point is it to get the value of C

$5=\frac{-7\times 6}{2}+C\phantom{\rule{0ex}{0ex}}5=-7\times 3+C\phantom{\rule{0ex}{0ex}}C=5+21=26$

so $y=\frac{-7n}{2}+26\phantom{\rule{0ex}{0ex}}y=-3.5n+26$

The slope intercept form is used to provide the equation of the straight line in the form of

$y=mx+c$

Where m is the slope of the straight line and c is the y intercept of the straight line .

The point are $(8,-2)\text{and}(6,5)$

$m=slope=\frac{{y}_{2}-{y}_{1}}{{x}_{2}-{x}_{1}}=\frac{5-(-2)}{6-8}=\frac{5+2}{-2}=\frac{-7}{2}$

Now as slope intercept form is

$y=mx+c$

Putting m we get $y=\frac{-7n}{2}+C$

Now substituting a point is it to get the value of C

$5=\frac{-7\times 6}{2}+C\phantom{\rule{0ex}{0ex}}5=-7\times 3+C\phantom{\rule{0ex}{0ex}}C=5+21=26$

so $y=\frac{-7n}{2}+26\phantom{\rule{0ex}{0ex}}y=-3.5n+26$

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