A sled traveling at a speed of 3.0 PSKms^-1ZSK slows to a stop 4.0 m from the point where its passenger rolled off. What is the magnitude of the horizontal net force that slows the 110 N sled?

Enrique Cunningham

Enrique Cunningham

Answered question

2022-12-26

A sled traveling at a speed of 3.0 ms1 slows to a stop 4.0 m from the point where its passenger rolled off. What is the magnitude of the horizontal net force that slows the 110 N sled?

Answer & Explanation

Elianna Bradley

Elianna Bradley

Beginner2022-12-27Added 8 answers

We employ: to determine the sled's acceleration.
v2=u2+2ad
Rearranging:
a=v2u22d=023224=98 ms2
The sled is slowing down when the acceleration is denoted by a minus sign because it is occurring in the opposite direction of the velocity.
We want to use Newton's Second Law to find the force:
F=ma
We're not given the mass of the sled, but we are told its weight is 110 N. We know the weight force is given by F=mg, so we can rearrange to find:
m=Fg=1109.8kg
So:
F=ma=1109.898=12.63N
The minus sign simply indicates that the force is acting in the opposite direction from the sled's initial motion, to reiterate.

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