A stone falls from a cliff and travels 24.5 m in the last second before it reaches the ground at the foot of the clif. Find the height of the cliff. (g=9.8 ms^(-2))

doctorfinger1ci

doctorfinger1ci

Answered question

2023-01-22

A stone falls from a cliff and travels 24.5m in the last second before it reaches the ground at the foot of the clif. Find the height of the cliff. (g=9.8ms-2)

Answer & Explanation

Gremoli9bs

Gremoli9bs

Beginner2023-01-23Added 10 answers

Step 1: We have:
Distance traveled in the last second = 24.5m
Gravitational acceleration g=9.8ms-2
Step 2: Formula
sn=u+g(n-12)s=ut+12gt2
Step 3: Calculation of time
sn=u+g(n-12)24.5=0+9.8(n-12)24.5=9.8n-4.99.8n=24.5+4.9n=29.49.8n=3
Thus, it takes 3s to reach the earth.
Step 4: Calculation of height
s=ut+12gt2=0×3+12×9.8×32=4.9×9=44.1m
So, the height of the cliff is 44.1m.

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