Energy is conventionally measured in Calories as well

Answered question

2022-05-06

Energy is conventionally measured in Calories as well as in joules. One Calorie in nutrition is 1 kilocalorie, which we define as 1 kcal = 4186 J. Metabolizing 1 gram of fat can release 9.00 kcal.

A student decides to try to lose weight by exercising. She plans to run up and down the stairs in a football stadium as fast as she can and as many times as necessary. Is this in itself a practical way to lose weight?

To evaluate the program, suppose she runs up a flight of 74 steps, each 0.173 m high, in 58.8 s. For simplicity, ignore the energy she uses in coming down (which is small). Assume that a typical efficiency for human muscles is 20.0%. This means that when your body converts 100 J from metabolizing fat, 20 J goes into doing mechanical work (here, climbing stairs). The remainder goes into internal energy. Assume the student's mass is 52.8 kg.

How many times must she run the flight of stairs to lose 1 pound of fat? (1 lb = 0.454 kg)

 

What is her average power output, in watts and in horsepower, as she is running up the stairs? (1hp = 746 W)
 

Answer & Explanation

alenahelenash

alenahelenash

Expert2022-06-05Added 556 answers

Given t=61.0 s, m=107.0 kg, k=0.20, g=9.81 m/s²
h = 85(0.150) = 12.75 m
E = (1 lb-fat)(37.8 kJ/g-fat)(454 g/lb) = 17.1 MJ
The energy needed to climb stairs once is given by:
E = mgh/k
So #n times student must run stairs to lose 1 lb fat is:
nE = 17.1 MJ
n = 17.1MJ*k/mgh = 225.54
Average power (energy per time) output is:
P = E/t = mgh/kt = 1097 W

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