Why is Newton's second law only second-order in position? For instance, could there exist higher-order masses m_i with F(x)=mx¨+sum_(i=3)^∞m_ix(i)?

Ryland Houston

Ryland Houston

Answered question

2022-09-20

Why is Newton's second law only second-order in position? For instance, could there exist higher-order masses m i with
F ( x ) = m x ¨ + i = 3 m i x ( i ) ?

Answer & Explanation

kregde84

kregde84

Beginner2022-09-21Added 10 answers

I think Newton's first law, linearity of motion, and the time-reversal symmetry strongly constrain the form of Newton's second law.
Generically, the linear relation between the position and the force is given by
F = β 0 x + β 1 d x d t + β 2 d 2 x d t 2 + β 3 d 3 x d t 3 + .
The time-reversal symmetry demands that all odd derivatives vanish, β 2 k + 1 = 0 for k = 0 , 1 , 2 . The spatial homogeneity demands β 0 = 0. Therefore,
F = β 2 d 2 x d t 2 + β 4 d 4 x d t 4 + = β 2 a + β 4 d 2 a d t 2 + .
Here a is the acceleration. The first law demands that, when F=0, the only solution is the trivial solution a=0. We see that, if all higher coefficients β 4 , β 6 , are not zero, there will be other solutions. Thus, the only possible form is
F = β 2 d 2 x d t 2 .

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