Since Force is a one-form (co-variant vector), is it more accurate to assert that F=ma^ug_(uv) where au is the acceleration vector, which is contra-variant, and g_(uv) is the metric tensor?

Deja Bradshaw

Deja Bradshaw

Answered question

2022-10-28

Since Force is a one-form (co-variant vector), is it more accurate to assert that F = m a u g u v where a u is the acceleration vector, which is contra-variant, and g u v is the metric tensor?

Answer & Explanation

Adenomacu

Adenomacu

Beginner2022-10-29Added 13 answers

The equation F = m a μ g μ ν is notationally unclear. You're right to note that tensor equations have to match types of tensors on both sides, but if we're being really careful about notation, then we have to note exactly what sort of tensor F is. If you mean F ν , then it is true that F ν = m a μ g μ ν , but it would be equally correct to write F ν = m a ν or F ν = m a ν . This is because in Einstein summation notation it is understood that F μ = g μ ν F ν and F μ = g μ ν F ν

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