The work done in one complete revolution of the moon around the earth is equal to: A) zero B) gravitational force x diameter of the orbit of the moon C) gravitational force x circumference of the orbit of the moon D) centripetal force x radius of the orbit of the moon

Aron Heath

Aron Heath

Answered question

2022-11-20

The work done in one complete revolution of the moon around the earth is equal to:
A) zero
B) gravitational force x diameter of the orbit of the moon
C) gravitational force x circumference of the orbit of the moon
D) centripetal force x radius of the orbit of the moon

Answer & Explanation

Incampo5in

Incampo5in

Beginner2022-11-21Added 10 answers

The necessary force required for the revolution of the moon around the Earth is provided by the gravitational force acting between the moon and the Earth. The direction of displacement of the moon is tangential to the circular path of revolution of the moon.
If F is the gravitational force and d is the displacement of the moon, the work done is given by,
W = F d cos θ
Here, θ is the angle between the direction of gravitational force and the direction of displacement of the moon.
Since the gravitational force acts in the radial direction of the path of the moon, the angle between the directions of force and displacement is θ = 90 .
Since cos 90 = 0, the work done in the revolution of the moon around the earth is zero.
Therefore, option A is correct.

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