Identify the center and radius of the circles 1) (x−1)2+(y+3)2=4 2) (x−2)2+(y−1)2=16 3) x2+(y−3)2=14 4) x2+4x+y2=32

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York

2021-08-08

Identify the center and radius of the circles
1)

{(x - 1)}^{2} + {(y + 3)}^{2} = 4

{(x - 2)}^{2} + {(y - 1)}^{2} = 16

x^{2} + {(y - 3)}^{2} = 14

x^{2} + 4 x + y^{2} = 32

Nichole Watt

Skilled2021-08-09Added 100 answers

{(x - h)}^{2} + {(y - k)}^{2} = r^{2}

(h, k) is the center and r is the radius of the circle.
1.

{(x - 1)}^{2} + {(y + 3)}^{2} = 4

{(x - 1)}^{2} + {(y - (- 3))}^{2} = 2^{2}

(1, - 3)

is the center and 2 is the radius of the circle.
2.

{(x - 2)}^{2} + {(y - 1)}^{2} = 16

{(x - 2)}^{2} + {(y - 1)}^{2} = 42

(2, 1) is the center and 4 is the radius of the circle.
3.

x^{2} + {(y - 3)}^{2} = 14

{(x - 0)}^{2} + {(y - 3)}^{2} = {(\sqrt{14})}^{2}

(0, 3)

is the center and

\sqrt{14}

is the radius of the circle.
4.

x^{2} + 4 x + y^{2} = 32

x^{2} + 4 x + y^{2} + 4 = 32 + 4

(x^{2} + 4 x + 4) + y^{2} = 36

{(x + 2)}^{2} + {(y - 0)}^{2} = 6^{2}

{(x - (- 2))}^{2} + {(y - 0)}^{2} = 6^{2}

(- 2, 0)

is the center and 6 is the radius of the circle.

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