What is the radius and center for (x−2)2+y2=16? A. r=16. center is (2,0) B. r=4. center is (-2,0) C. r=16. center is (-2,0) D. r=4. center is (2,0)

"What is the radius and center for (x−2)2+y2=16?..." was answered by students like you

beljuA

2021-08-09

What is the radius and center for

{(x - 2)}^{2} + y^{2} = 16 ?

r = 16

. center is (2,0)
B.

r = 4

. center is (-2,0)
C.

r = 16

. center is (-2,0)
D.

r = 4

. center is (2,0)

Yusuf Keller

Skilled2021-08-10Added 90 answers

Step 1
Given equation is

{(x - 2)}^{2} + y^{2} = 16

find radius and center
Step 2
given equation is a circle
standard form of an equation of a circle is

{(x - h)}^{2} + {(y - k)}^{2} = r^{2}

center

= (h, k)

radius

= r

lets write the given equation in standard form

{(x - 2)}^{2} + {(y - 0)}^{2} = 4^{2}

center

= (2, 0)

radius

= r = 4

Thus D is a correct option.

Do you have a similar question?

Recalculate according to your conditions!

Didn't find what you were looking for?