A figure is made up of a triangle and a square, where the triangle's base b△ is a side of a square l◻. h△ l△=s△ Pfigure=56cm Afigure=?

Afigure=A◻+A△ A◻=l◻2 l◻=Pfigure−2×l△3 =56−203 =363 =12cm A△=12×bh =12×8×12 =48cm2 Afigure=122+48 =144+48 =192cm2

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High School
Geometry
High school geometry
Solid Geometry

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Answered question

2021-08-17

A figure is made up of a triangle and a square, where the triangle's base $b_{△}$ is a side of a square $l_{◻}$ .
$h_{△}$
$l_{△} = s_{△}$
$P_{f i g u r e} = 56 c m$
$A_{f i g u r e} = ?$

Answer & Explanation

crocolylec

Skilled2021-08-18Added 100 answers

$A_{f i g u r e} = A_{◻} + A_{△}$
$A_{◻} = l_{◻}^{2}$
$l_{◻} = \frac{P_{f i g u r e} - 2 \times l_{△}}{3}$
$= \frac{56 - 20}{3}$
$= \frac{36}{3}$
=12cm
$\underset{△}{A} = \frac{1}{2} \times b h$
$= \frac{1}{2} \times 8 \times 12$
$= 48 c m^{2}$
$A_{f i g u r e} = 12^{2} + 48$
=144+48
$= 192 c m^{2}$

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