What is the radius and center for (x−2)2+y2=16? A. r=16; center is (2,0) B. r=4; center is (-2,0) C. r=16; center is (-2,0) D. r=4; center is (2,0)

Answered: "What is the radius and center for (x−2)2+y2=16?..."

Bergen

2021-09-21

What is the radius and center for

{(x - 2)}^{2} + y^{2} = 16 ?

r = 16

; center is (2,0)
B.

r = 4

; center is (-2,0)
C.

r = 16

; center is (-2,0)
D.

r = 4

; center is (2,0)

Alix Ortiz

Skilled2021-09-22Added 109 answers

Step 1
Given equation is

{(x - 2)}^{2} + y^{2} = 16

find radius and center
Step 2
given equation is a circle
standard form of an equation of a circle is

{(x - h)}^{2} + {(y - k)}^{2} = r^{2}

center

= (h, k)

radius

= r

lets write the given equation in standard form

{(x - 2)}^{2} + {(y - 0)}^{2} = 4^{2}

center

= (2, 0)

radius

= r = 4

Thus D is a correct option.

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