Step 1 Solving by similarity of triangle Step 2 9n△ABCand△CDE, m&lt;ABC=m&lt;CDE (Given) andm&lt;ACB=m&lt;DCE So △ABC is similar to △CDE. ⇒ABDE=CBCD ⇒57⋅5=x3 ⇒x=157⋅5=2 x=2

Get the answer to "Find the length x. "

High School
Geometry
High school geometry
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nagasenaz

Answered question

2020-10-18

Find the length x.

Answer & Explanation

Alannej

Skilled2020-10-19Added 104 answers

Step 1
Solving by similarity of triangle
Step 2

$9 n △ A B C and △ C D E$ ,
$m < A B C = m < C D E$ (Given)
$and m < A C B = m < D C E$
So $△ A B C$ is similar to $△ C D E$ .
$\Rightarrow \frac{A B}{D E} = \frac{C B}{C D}$
$\Rightarrow \frac{5}{7 \cdot 5} = \frac{x}{3}$
$\Rightarrow x = \frac{15}{7 \cdot 5} = 2$
x=2

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