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amanf

Answered question

2021-01-15

To determine:To Find:the measure of side VC in the figure shown such that VA

Benedict

Skilled2021-01-16Added 108 answers

Calculation:
Since, plane of

△ A^{'} B^{'} C^{'}

is similar to the plane of

△ A B C

Since, ABCD is a parallelogram.

∠ B = ∠ V ∴

(Common)

∠ V A B = ∠ V A^{'} B^{'} ∴

(Corresponding angle in two similar plane)
Therefore by AA similarity,

△ V A B \sim △ V A^{'} B^{'}

Ratio of corresponding sides in two similar triangles is equal.

\frac{V A}{V A^{'}} = \frac{V C}{V C^{'}}

\frac{V A^{'} + \forall^{'}}{V A^{'}} = \frac{V C}{V C^{'}}

\frac{15 + 20}{15} = \frac{V C}{18}

V C = \frac{18 \times 35}{15}

VC=42
Therefore, the answer is 42.

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