Yulia

2021-01-22

To determine:To Find:the measure of side BB

Bertha Stark

Skilled2021-01-23Added 96 answers

Calculation:

Since, plane of$\mathrm{\u25b3}{A}^{\prime}{B}^{\prime}{C}^{\prime}$ is similar to the plane of $\mathrm{\u25b3}ABC$

Since, ABCD is a parallelogram.

$\mathrm{\angle}V=\mathrm{\angle}V\therefore$ (Common)

$\mathrm{\angle}VAB=\mathrm{\angle}V{A}^{\prime}{B}^{\prime}\therefore$ (Corresponding angle in two similar plane)

Therefore by AA similarity,$\mathrm{\u25b3}VAB\sim \mathrm{\u25b3}V{A}^{\prime}{B}^{\prime}$

Ratio of corresponding sides in two similar triangles is equal.

$\frac{VA}{V{A}^{\prime}}=\frac{VC}{V{C}^{\prime}}$

$\frac{V{A}^{\prime}+{\mathrm{\forall}}^{\prime}}{V{A}^{\prime}}=\frac{VB}{V{B}^{\prime}}$

$\frac{15+20}{15}=\frac{49}{V{B}^{\prime}}$

$V{B}^{\prime}=\frac{15\times 49}{35}$

VB'=21

VB=BB'+VB'

49=BB+21

BB'=28

Therefore, the answer is 28.

Therefore, the answer is 42.

Since, plane of

Since, ABCD is a parallelogram.

Therefore by AA similarity,

Ratio of corresponding sides in two similar triangles is equal.

VB'=21

VB=BB'+VB'

49=BB+21

BB'=28

Therefore, the answer is 28.

Therefore, the answer is 42.

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