I'm having trouble finding out the first step to this problem. So far all I have is: <math xmlns

mravinjakag

mravinjakag

Answered question

2022-06-19

MathJax(?): Can't find handler for document MathJax(?): Can't find handler for document I'm having trouble finding out the first step to this problem.
So far all I have is:
x ( t ) = 6 cos ( t ) + 6 y ( t ) = 6 sin ( t )
Find parametric equations for the arc of a circle of radius 6 from P = ( 0 , 0 ) to Q = ( 12 , 0 ).
x ( t ) = ___ y ( t ) = ___ ___   <   t < ___

Answer & Explanation

Haggar72

Haggar72

Beginner2022-06-20Added 25 answers

You already almost completed the problem. The only other question is what values of t should we use. The starting point is given as (12,0), which corresponds to t = 0 or t = 2 π in your equation. The ending point is given as (0,0), which corresponds to t = π in your equation. Thus, if we restrict ourselves to 0 < t < 2 π, the answer could either be 0 < t < π or π < t < 2 π, depending on if you want the top or bottom arc of the circle.

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