Earlier last week I realized I needed to ship a large volume of things domestically. Of course, I de

George Bray

George Bray

Answered question

2022-06-23

Earlier last week I realized I needed to ship a large volume of things domestically. Of course, I decided that I wanted to do so as cheaply as possible.

I first looked at USPS standard post rates. I noted that if the "combined length and girth" of a box exceeds 108", then the package becomes significantly more expensive, as it uses the "oversized" price bracket, so I resolved not to exceed this size limit. The length of a box is defined as its longest dimension, and its girth is defined as the perimeter around the rectangle to which the length is orthogonal – in other words, the girth is 2 w + 2 h.

However, because I have much to ship, I also would like to maximize the volume of such a box while not exceeding this limit. This turns into a maximization problem with a constraint:

Maximize V ( x ) = l w h, while satisfying 108 >= l + 2 w + 2 h.

This seems pretty simple, but I'm not sure how to handle the three nominally independent variables l, w, and h. Because I did not want to wait or rely on my faulty math skills, I ultimately asked Wolfram|Alpha to solve this for me, yielding a box of size 36"x18"x18". This makes intuitive sense, to a degree, but I would like a hint as to how I could have proceeded to solve this on my own.

Answer & Explanation

Samantha Reid

Samantha Reid

Beginner2022-06-24Added 22 answers

You asked for a hint. Here are two.

(1) You certainly want l + 2 w + 2 h = 108.

(2) If you temporarily fix l, you have a certain amount to make a rectangle with w and h. The maximum area would be to make a square out of w and h (i.e., w = h).
Layla Velazquez

Layla Velazquez

Beginner2022-06-25Added 11 answers

The AM/GM inequality shows immediately that the maximum volume occurs uniquely when l = 2 w = 2 h.

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