The area of a trapezium is 475 c m 2 and the height is 19 cm .Find the lengths of its two paallel sides if one side is 4 cm greater than the other.

Question

The area of a trapezium is   475  c      m          2        and the height is 19 cm .Find the lengths of its two paallel sides if one side is 4 cm greater than the other.

gozaderaradiox5 · Accepted Answer

Step 1We know that the area of a trapezium isA       1    2    ×  (  sum of parallel lines  )  ×  (  distance between parallel lines  )Step 2  A  =  475  c      m          2        A  =  19Let one parallel side length xAnother parallel side length   =  x  +  4  A  =      1    2    ×  (  x  +  x  +  4  )  ×  19  475  =      1    2    ×  (  2  x  +  4  )  ×  19  2  x  +  4  =            2      ×      475        19    2  x  +  4  =  50  2  x  =  46  x  =  23Second parallel side   x  +  4  =  23  +  4  =  27  c  m

delirija7z · Accepted Answer

Consider x cm as the smaller side of the trapeziumSo the larger parallel can be written as   (  x  +  4  )  c  mWe know that the area of trapezium       1    2    × sum of parallel sides x heightBy substituting the values  475  =      1    2    ×  (  x  +  (  x  +  4  )  )  ×  19On further calculation  25  =      1    2    ×  (  2  x  +  4  )So we get  50  =  2  x  +  4By subtraction  2  x  =  50  −  42  x  =  46By division  x  =  23  c  mSo we get Larger parallel side   (  x  +  4  )  =  23  +  4  =  27  c  mTherefore, the length of two parallel sides is 23cm and 27cm.

The area of a trapezium is 475 cm^2 and the height is 19 cm. Find the lengths of its two paallel sides if one side is 4 cm greater than the other

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