We know the asymptotic behavior of the scalar geometric sequence u_{n+1}=qu_{n} with respect to the values of q. That is, |q|<1 implies lim_n u_n=0, q=1 implies u_n is constant, etc.

yasusar0

yasusar0

Answered question

2022-07-21

Asymptotic behavior of the geometric sequence U n + 1 = Q U n in a probability problem
We know the asymptotic behavior of the scalar geometric sequence u n + 1 = q u n with respect to the values of q. That is, | q | < 1 implies lim n u n = 0, q = 1 implies u n is constant, etc.
Now I am just asking myself the same question about the geometric sequence U n + 1 = Q U n , where Q is a 2 × 2 matrix and U n is a two dimensional vector.

Answer & Explanation

Tamoni5e

Tamoni5e

Beginner2022-07-22Added 14 answers

Step 1
If matrix and vector norms are compatible in the way that Q x Q x , then Q < 1 implies Q n x 0 for all x.
Step 2
If Q > 1 then Q could be the identity or a rotation matrix, with the obvious consequences on convergence of Q n x.
If Q > 1 then Q n x is not guaranteed to be unbounded. Take Q = ( 2 0 1 0 ) and x = ( 1 0 ) or x = ( 0 1 )

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