Bill, Mary and Tom have coins with respective probabilities p_1, p_2, p_3 of turning up heads. They toss their coins independently at the same times. What is the probability that neither Bill nor Tom get a head before Mary?

Freddy Friedman

Freddy Friedman

Answered question

2022-07-20

Probability about a geometric distribution
Bill, Mary and Tom have coins with respective probabilities p 1 , p 2 , p 3 of turning up heads. They toss their coins independently at the same times.
What is the probability that neither Bill nor Tom get a head before Mary?

Answer & Explanation

Jaylynn Huffman

Jaylynn Huffman

Beginner2022-07-21Added 14 answers

Step 1
Each group of simultaneous tosses has three possible outcomes. If Mary obtains "head", the game is over with positive outcome. If Bill and/or Tom obtains "head" and Mary doesn't, the game is over with negative outcome. If no-one obtains "head", the game continues with the same probabilities as before. Thus, the probability of a positive outcome is the sum of three contributions:
p = p 2 1 + ( 1 ( 1 p 1 ) ( 1 p 3 ) ) ( 1 p 2 ) 0 + ( 1 p 1 ) ( 1 p 2 ) ( 1 p 3 ) p = p 2 1 + ( 1 p 1 ) ( 1 p 2 ) ( 1 p 3 ) p .
Step 2
Solving for p yields p = p 2 1 ( 1 p 1 ) ( 1 p 2 ) ( 1 p 3 ) .

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