A pair of dice are repeatedly rolled until the two sum to ge 10. The expected number of times the pair is rolled is?

ljudskija7s

ljudskija7s

Answered question

2022-08-10

Geometric distribution expected number of rolls
A pair of dice are repeatedly rolled until the two sum to 10. The expected number of times the pair is rolled is?
I understand how to apply the geometric to get the probability of an event, but I do not understand how to use it to get the expected number of rolls (in this case) to achieve a certain result.

Answer & Explanation

Malcolm Mcbride

Malcolm Mcbride

Beginner2022-08-11Added 20 answers

Step 1
First, the probability that two dice sum up to 10 is 16 since there are six possible events, {46,55,56,64,65,66}. Thus, if X counts the number of rolls, then Pr ( X = k ) = 1 6 . You can now simply use the fact that E ( X ) = 1 p and get 6. Alternatively, here is the calculation:
E ( X ) = k = 1 k Pr ( X = k ) = k = 1 k ( 5 6 ) k 1 1 6 = 1 6 k = 0 k ( 5 6 ) k 1
Step 2
Let f ( x ) = x 1 x . Then for x ( 0 , 1 ), we have f ( x ) = k = 0 x k . Thus, k = 0 k x k 1 = f ( x ) = 1 ( 1 x ) 2 . Therefore, E ( X ) = 1 6 f ( 5 6 ) = 1 6 1 ( 1 6 ) 2 = 6.

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