How do you find the perimeter of a triangle whose coordinates are (10,2) and (7,-3)?

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Dominic Paul · Accepted Answer

Assuming the third coordinate is the origin (0,0)Using the Pythagorean Theorem:Distance (0,0) to (10,2)                              10          2                +                  2          2                      =                  104            Distance (0,0) to (7,-3)                              7          2                +                              (            -            3            )                    2                      =                  58            Distance (10,2) to (7,−3)                              3          2                +                  5          2                      =                  34            Perimeter =                     104              +                  58              +                  34            (perhaps this would have been a prettier answer with a third point other than the origin)

How do you find the perimeter of a triangle whose coordinates are (10,2) and (7,-3)?

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