Integral over solid angle in Cartesian coordinates <br> bar{f} = 1/(4pi) int_{Omega} int f sin theta d theta d phi
Moselq8
Answered question
2022-08-12
I have an integral that is an average of some (unknown) function f over solid angle:
Answer & Explanation
Avah Leonard
Beginner2022-08-13Added 21 answers
The most obvious choice for the surface is a sphere of radius 1. For the sphere , so .
Step 2
Also , so on the surface. Note that you still want to use your expression for .
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