Makayla Eaton

2022-08-16

Distance between (9,2,0) and (0,6,0)?

Payton Mcbride

Beginner2022-08-17Added 18 answers

Use the 3-d version of the distance formula

$\mid \overline{\underline{{\frac{a}{a}}{d=\sqrt{{({x}_{2}-{x}_{1})}^{2}+{({y}_{2}-{y}_{1})}^{2}+{({z}_{2}-{z}_{1})}^{2}}}{\frac{a}{a}}\mid}}$

where $({x}_{1},{y}_{1},{z}_{1})\phantom{\rule{1ex}{0ex}}\text{and}\phantom{\rule{1ex}{0ex}}({x}_{2},{y}_{2},{z}_{2})\phantom{\rule{1ex}{0ex}}\text{are 2 coordinate points}$

here the 2 points are (9 ,2 ,0) and (0 ,6 ,0)

let $({x}_{1},{y}_{1},{z}_{1})=(9,2,0)\phantom{\rule{1ex}{0ex}}\text{and}\phantom{\rule{1ex}{0ex}}({x}_{2},{y}_{2},{z}_{2})=(0,6,0)$

$d=\sqrt{{(0-9)}^{2}+{(6-2)}^{2}+{0}^{2}}=\sqrt{81+16}=\sqrt{97}\approx 9.849$

$\mid \overline{\underline{{\frac{a}{a}}{d=\sqrt{{({x}_{2}-{x}_{1})}^{2}+{({y}_{2}-{y}_{1})}^{2}+{({z}_{2}-{z}_{1})}^{2}}}{\frac{a}{a}}\mid}}$

where $({x}_{1},{y}_{1},{z}_{1})\phantom{\rule{1ex}{0ex}}\text{and}\phantom{\rule{1ex}{0ex}}({x}_{2},{y}_{2},{z}_{2})\phantom{\rule{1ex}{0ex}}\text{are 2 coordinate points}$

here the 2 points are (9 ,2 ,0) and (0 ,6 ,0)

let $({x}_{1},{y}_{1},{z}_{1})=(9,2,0)\phantom{\rule{1ex}{0ex}}\text{and}\phantom{\rule{1ex}{0ex}}({x}_{2},{y}_{2},{z}_{2})=(0,6,0)$

$d=\sqrt{{(0-9)}^{2}+{(6-2)}^{2}+{0}^{2}}=\sqrt{81+16}=\sqrt{97}\approx 9.849$

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