Distance between (2,5) and (9,1)?

Question

Janiah Hoffman · Accepted Answer

Let distance be d. Then:                    ×                    d      2        =                  (        Δ        x        )            2        +                  (        Δ        y        )            2                      ×        ×        ×        ×        ×        x             (Pythagorous&#039; Theorem)      ⇒                            d          2                      =                                        (                                                            x                  2                                -                                  x                  1                                                      )                    2                +                              (                                                            y                  2                                -                                  y                  1                                                      )                    2                          ⇒    d    =                                        (                          1                        -                          5                        )                    2                +                              (                          9                        -                          2                        )                    2                                        ×        x              =                                        4                    2                +                              7                    2                                        ×        x              =          65

Distance between (2,5) and (9,1)?

Open question

Answer & Explanation

New Questions in High school geometry