I need to find the volume bounded by the following surfaces: x^2+y^2=2z, x^2+y^2=3-z.

zabuheljz

zabuheljz

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2022-08-16

Find the volume bounded by the following surfaces
I need to find the volume bounded by the following surfaces:
x 2 + y 2 = 2 z
x 2 + y 2 = 3 z
I don't know how to proceed in solving this exercise, all I could think of was trying to make a system of these 2 and get z = 1. I just wanna understand how am I supposed to proceed in finding the boundaries, no need to evaluate the integral.

Answer & Explanation

cydostwng6c

cydostwng6c

Beginner2022-08-17Added 13 answers

Step 1
You have x 2 + y 2 = 2 ( 3 x 2 y 2 ) x 2 + y 2 = 6 2 x 2 2 y 2 3 x 2 + 3 y 2 = 6
x 2 + y 2 = 2, which gives you the circle of center (0,0) and radius 2 . We can now compute the integral in cylindrical coordinates doing the following calculations
V d x d y d z = 0 2 π 0 2 ρ 2 2 3 ρ 2 ρ d z d ρ d θ = 0 2 π d θ 0 2 ρ ( 3 3 ρ 2 2 ) d ρ =
= 2 π 0 2 3 ρ 3 ρ 3 2 d ρ = 2 π 3 ρ 2 2 3 ρ 4 8 | 0 2 = 3 π .

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