I want to maximize the volume of a box, with sides parallel to the xy, xz and yz-planes, with the box inside of an ellipsoid x^2/a^2+y^2/b^2+z^2/c^2=1

Anito49

Anito49

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2022-08-20

Basic questions about finding a volume formula for a box inside of an ellipsoid,
I want to maximize the volume of a box, with sides parallel to the xy, xz and yz-planes, with the box inside of an ellipsoid
x 2 a 2 + y 2 b 2 + z 2 c 2 = 1
So, my answer, using Lagrange multipliers, turns out to be wrong, at least comparing my work to the solution given.
I had thought to maximize "length times height times width", so I figured that the objective function should be f ( x , y , z ) = x y x z y z = x 2 y 2 z 2 .
The solution instead maximizes a different function:
f ( x , y , z ) = 2 x 2 y 2 z
I am guessing that the solution is indeed correct? And the point I probably missed was this: the ellipsoid is centered at 0. So, sketching out the box on paper, "length times height times width" does look like 2 x 2 y 2 z.
What do you think?
Also, how does an equation of an ellipsoid not centered at 0 look like? Would it be something like this:
( x 1 ) 2 a 2 + ( y 2 ) 2 b 2 + ( z 3 ) 2 c 2 = 1 ?
would this be an ellipsoid centered at (1,2,3)?

Answer & Explanation

Yaretzi Melendez

Yaretzi Melendez

Beginner2022-08-21Added 7 answers

Step 1
The correct equation for the ellispoid centered at the origin is
x 2 a 2 + y 2 b 2 + z 2 c 2 = 1.
It is obvious that the resulting (optimal) box would be centered at the origin.
Step 2
If we denote one of the vertices of the box by (x, y, z), then the sides have lengths 2x, 2y, 2z assuming x , y , z > 0. With this, the volume is 8xyz.
torfuqx

torfuqx

Beginner2022-08-22Added 1 answers

Explanation:
A dimension check would’ve told you that your expression for the volume of the inscribed box was incorrect. A volume should have a dimension of length 3 , but x 2 y 2 z 2 has a dimension of length 6 .

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