The point (x, y) is chosen randomly in the unit square. What is the conditional probability of x^2+y^2 leq 1/4 given that xy leq 1/16

Hollywn

Hollywn

Open question

2022-08-19

A problem on conditional geometric probability
The point (x, y) is chosen randomly in the unit square. What is the conditional probability of x 2 + y 2 1 / 4 given that x y 1 / 16.
I started solving this and while calculating I got some very unpleasant numbers but the problem is not marked as difficult in this book where I found it. So I start suspecting that I am having some conceptual mistake.
The two curves intersect at x = 2 + 3 / 4 and at x = 2 3 / 4
Now I have to find a few areas via definite integrals. Is that what this problem is about?

Answer & Explanation

micelarnyiz

micelarnyiz

Beginner2022-08-20Added 8 answers

Step 1
x y 1 16 iff 2 x y 1 8 .
Conditional on this, x 2 + y 2 1 4 iff 2 x y 1 8 .
Conditional on this, x 2 + y 2 1 4 iff x 2 + 2 x y + y 2 = ( x + y ) 2 3 8 iff x + y 3 8 .
Step 2
Now do you know how to calculate the probability that the sum of two random numbers is less than a given number?
nascarchic839e9

nascarchic839e9

Beginner2022-08-21Added 2 answers

Explanation:
Suppose that x y 1 16 .. Then x 2 + y 2 1 4 ( x + y ) 2 3 8 . This should lead to an easier way to approach it.

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