So, the volume of the solid of revolution isVolume = V = π ∫ a b ( 9 − x 2 ) 2 d x .To find the volume, integrate from x =??? to x = 3

Question

So, the volume of the solid of revolution isVolume =   V  =  π      ∫    a    b    (  9  −      x    2        )    2    d  x  .To find the volume, integrate from x =??? to x = 3

Drew Patel · Accepted Answer

V  =  π      ∫    a    b    (  9  −      x    2        )    2    d  xTo find volume intergrate from x=0 to x=3  V  =  π      ∫    0    3    (      x    4    −  18      x    2    +  81  )  d  x    =  π      [              x      5        5    −            18              x        3              3    +  81  x            ]        0    3      =  π  (            3      5        5    −  0  )  −  (            18      ⋅              3        3              3    −  0  )  +  (  81  ⋅  3  −  0  )    =  π  (      243    5    −      486    3    +  243  )    =  −      1944    15    π

So, the volume of the solid of revolution is Volume = V = pi int_a^b (9 - x^2)^2 dx. To find the volume, integrate from x = (?) to x = 3

Open question

Answer & Explanation

New Questions in High school geometry