A hotel is in the shape of a cylinder, with a cylinder foundation. The circumference of the foundation is 6 times the radius, increased by 12.88ft. Find the radius of the circular foundation. (use 3.14 as an approximation for π)

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A hotel is in the shape of a cylinder, with a cylinder foundation. The circumference of the foundation is 6 times the radius, increased by 12.88ft. Find the radius of the circular foundation. (use 3.14 as an approximation for   π)

Harmony Horn · Accepted Answer

The circumfrence of any circle is   2  π  r.The problem says that the circumfrence is = 6r+12.88ftYou just set these two equal to each other and solve for r.  2  π  r  =  6  r  +  12.88 (subtract 6r from both sides to getr&#039;s on same side)  2  π  r  −  6  r  =  12.88 (factor out the r)  r  (  2  π  −  6  )  =  12.88 (divide both sides by   2  π  −  6)  r  =  12.88      /    (  2  π  −  6  )r=45.48ftYour problem says to use an approximation of 3.14 for   π. This will result in your answer being:r=46ft

streutexw · Accepted Answer

circumference is   2  ∗  π  ∗  rso the circumference is equal to 6 times the radius plus 12.88ft  2  ∗  π  ∗  r  =  6  r  +  12.886.28r = 6r + 12.88*subtract 6r from both sides.28r = 12.88*divide .28 on both sidesr = 46 ft

A hotel is in the shape of a cylinder, with a cylinder foundation. The circumference of the foundation is 6 times the radius, increased by 12.88ft. Find the radius of the circular foundation. (use 3.14 as an approximation for pi )

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