Distance between (-1,15,3) and (3,14,5)?

Question

Genesis Rosario · Accepted Answer

using the 3-dimensional form of the                             distance formula                  •                  x              d    =                                        (                          x              2                        -                          x              1                        )                    2                +                              (                          y              2                        -                          y              1                        )                    2                +                              (                          z              2                        -                          z              1                        )                    2                                let                     (              x        1            ,              y        1            ,              z        1            )        =          (      -      1      ,      15      ,      3      )        ,          (              x        2            ,              y        2            ,              z        2            )        =          (      3      ,      14      ,      5      )            d    =                                        (            3            +            1            )                    2                +                              (            14            -            15            )                    2                +                              (            5            -            3            )                    2                                        d              =                  16        +        1        +        4              =          21        ≈    4.58

Distance between (-1,15,3) and (3,14,5)?

Answered question

Answer & Explanation

New Questions in High school geometry