Distance between (10,15,-2) and (12,-2,15)?

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Lilliana Mason · Accepted Answer

using the 3-dimensional form of the                             distance formula                  •                  x              d    =                                        (                          x              2                        -                          x              1                        )                    2                +                              (                          y              2                        -                          y              1                        )                    2                +                              (                          z              2                        -                          z              1                        )                    2                                let                     (              x        1            ,              y        1            ,              z        1            )        =          (      10      ,      15      ,      -      2      )                     and                         (              x        2            ,              y        2            ,              z        2            )        =          (      12      ,      -      2      ,      15      )            d    =                                        (            12            -            10            )                    2                +                              (            -            2            -            15            )                    2                +                              (            15            +            2            )                    2                                        d              =                  4        +        289        +        289              =          582        ≈    24.12

Distance between (10,15,-2) and (12,-2,15)?

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