Distance between (5,12) and (10,2)?

Question

Carina Moon · Accepted Answer

Let distance be d. Then                    ×                    d      2        =                  (        Δ        x        )            2        +                  (        Δ        y        )            2                      ×        ×        ×        ×        ×        x             (Pythagorous&#039; Theorem)      ⇒                            d          2                      =                                        (                                                            x                  2                                -                                  x                  1                                                      )                    2                +                              (                                                            y                  2                                -                                  y                  1                                                      )                    2                          ⇒    d    =                                        (                          10                        -                          5                        )                    2                +                              (                          2                        -                          12                        )                    2                                        ×        x              =                                        5                    2                +                              10                    2                                        ×        x              =                            25                +                  100                                        ×        x              =    5          5

Distance between (5,12) and (10,2)?

Answered question

Answer & Explanation

New Questions in High school geometry