John and Ron play basketball 10 times. The probability that John wins in single round = 0.4. The probability that Ron wins in single round = 0.3. The probability that there is equality between them in a single round = 0.3. The "Winner" is defined to be the first to win a single round. The rotations are different and independent. What is the probability that John is the Winner?

Gardiolo0j

Gardiolo0j

Answered question

2022-09-03

How can i solve this question with Geometric distribution or random variables?
I tried have tried using a 'Geometric distribution', but it hasn't worked.
John and Ron play basketball 10 times. The probability that John wins in single round = 0.4. The probability that Ron wins in single round = 0.3. The probability that there is equality between them in a single round = 0.3. The "Winner" is defined to be the first to win a single round.
The rotations are different and independent.
What is the probability that John is the Winner?

Answer & Explanation

Rihanna Blanchard

Rihanna Blanchard

Beginner2022-09-04Added 13 answers

Step 1
Given that there are exactly 10 rounds, the probability of having no winner by the end of the 10 rounds is 0.310. Then we know that the probability of having a winner is 1 0.3 10 .
Step 2
Such probability should be apportioned between John and Ron in the ratio 0.4/0.3. So the probability that John wins is 4 7 ( 1 0.3 10 )
ohgodamnitw0

ohgodamnitw0

Beginner2022-09-05Added 2 answers

Explanation:
Since they only play 10 times, the probability that John wins is equal to the sum of probabilities that John wins in the i-th round:
P = i = 1 10 ( 0.3 i 1 × 0.4 ) = 0.4 × 1 0.3 10 0.7 where the probability that John wins in the i-th round is 0.3 i 1 × 0.4 because the first i 1 rounds were all draws.

Do you have a similar question?

Recalculate according to your conditions!

New Questions in High school geometry

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?