A company has five employees on its health insurance plan. Each year, each employee independently has an 80% probability of no hospital admissions. If an employee requires one or more hospital admissions, the number of admissions is modeled by a geometric distribution with a mean of 1.50. The numbers of hospital admissions of different employees are mutually independent. Each hospital admission costs 20,000. Calculate the probability that the company’s total hospital costs in a year are less than 50,000.

Haiden Meyer

Haiden Meyer

Answered question

2022-10-08

Why is the sum of probability is not equal to 1 in a geometric distribution?
A company has five employees on its health insurance plan. Each year, each employee independently has an 80% probability of no hospital admissions. If an employee requires one or more hospital admissions, the number of admissions is modeled by a geometric distribution with a mean of 1.50. The numbers of hospital admissions of different employees are mutually independent.
Each hospital admission costs 20,000.
Calculate the probability that the company’s total hospital costs in a year are less than 50,000.
The probability of each employee has at least one hospital admissions is ( 0.2 1 ) / ( 1 2 / 3 ) = 0.6 instead of 0.2. Why is that?

Answer & Explanation

Joel Reese

Joel Reese

Beginner2022-10-09Added 17 answers

Step 1
If the employee has a hospital admission, the number of admissions is geometrically distributed with mean 3 2 . That is the probability of exactly k admissions is p ( 1 p ) k 1 ,   k = 1 , 2 , and the mean is 1 p so p = 2 3 ..
Step 2
However, these probabilities are conditional probabilities, contingent on the employee's having had at least one admission (probability .2.) Therefore the probability p k that an employee has exactly k admissions is p k = { .8 , k = 0 .4 3 k , k > 0

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