On the segment [0,1] two numbers X, Y are being randomly selected. Find the probability that X+Y leq 1 and X-Y>0.1.

mafalexpicsak

mafalexpicsak

Answered question

2022-10-17

Geometric probability - line segment
On the segment [0,1] two numbers X, Y are being randomly selected. Find the probability that X + Y 1 and X Y > 0.1.

Answer & Explanation

n8ar1val

n8ar1val

Beginner2022-10-18Added 12 answers

Step 1
Lets draw a plane and use the x-coordinate of any point as the value of the number X and y-coord as a value of Y so that every point "equals" one pair of numbers. You know that both X and Y are between 0 and 1, so we draw a square with the side-length of 1 as a hole field of possible outcomes. We now should draw the situations that fit our requests. All of the "good" points should be below the line y = 1 x as we want that sum to be less or equal to 1.
Step 2
On the other hand, we want X Y to be greater than 0.1 so the points should also be to the right of the line y = x 0.1 (so while the y is the same as on the line x gets greater). We get an area fenced by all our lines that fits our requests. Thus we calculate its area and divide it by 1 as that's the area of a hole square
Cale Terrell

Cale Terrell

Beginner2022-10-19Added 3 answers

Step 1
lets say we have to choose two variables x and y from [0,1]. it can be demonstrated on 2D graph. the total number of pairs of points(x,y) where x,y are in range[0,1] may be represented by the area of square formed by lines x = 1 , y = 1 , x = 0 , y = 0. This area (which is 1 square unit) represents the total possible combinations of x and y such that x is in[0,1] as well y.
Step 2
The points(or the combinations of x and y) which satisfies x + y 1 are those points which are below the line x + y = 1 in the plane.and likewise the points satisfying x y > 0.1 lies below the line x y = 0.1 in that plane. so the area representing the points which satisfy above all constraints lies between the lines x y = 0.1 , y = 0 , x + y = 1 which is 0.2025 so the probability is equal to area representing allowed points divided by the area of total square = 0.2025

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