Getting the minimum radius of curvature of a conic section

Vincent Norman

Vincent Norman

Answered question

2022-10-23

Getting the minimum radius of curvature of a conic section
I am fairly new to this forum and since I am not directly from a mathmetics background I recently ran into a problem I cannot solve.
What I am trying to do is to intersect a cone at a specific angle and want to receive the minimum radius of curvature. I know how to do it for a cylinder and I also know that I will get either an ellipse, a parabola or a hyperbole for a conic section, but I cannot find a source for either the euqtion of the intersection nor the minimum radius of curvature/curvature itself.
I found some theoretical proofs for the different intersections, but unfortunately the math behind it was a bit too high for me.
Is there maybe a short and clear answer to this question? Or can someone refer me to an other sourve where I could the infromation from?

Answer & Explanation

Kason Gonzales

Kason Gonzales

Beginner2022-10-24Added 15 answers

Step 1
First of all, the minimum radius of curvature for a conic section occurs at a vertex, and it has the same length as the semi-latus rectum of the conic, that is b 2 / a for an ellipse or hyperbola, where a and b are as usual the semiaxes.
The values of a and b depend not only on the inclination of the intersecting plane, but also on the distance of that plane from the vertex of the cone. I'll express them as a function of the distances m and n of the vertices (of the ellipse or hyperbola) from the vertex of the cone. If u is the semi-aperture angle of the cone, we have:
4 a 2 = m 2 + n 2 2 m n cos 2 u , b 2 = m n sin 2 u , where sign − must be taken for an ellipse and sign + for a hyperbola.
Step 2
It follows that the minimum radius of curvature is r M I N = 2 m n sin 2 u m 2 + n 2 2 m n cos 2 u .
For a parabola, you just need to take the limit of the above result for n :
r M I N = 2 m sin 2 u .

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