Suppose we are given a convex n-gon and all possible pairs of non adjacent vertices are joined to form chords. Let f(n) be the number of pairs of intersecting chords. So f(4)=1,f(5)=5. I want to determine f(n) in general.

Maribel Vang

Maribel Vang

Answered question

2022-10-29

Suppose we are given a convex n-gon and all possible pairs of non adjacent vertices are joined to form chords. Let f(n) be the number of pairs of intersecting chords. So f ( 4 ) = 1 , f ( 5 ) = 5. I want to determine f(n) in general.
Some thoughts:
Its not clear to me as to why f(n) is well defined.
f ( n ) = f ( n 1 ) + something. I want to determine that something.
Is f(n) an upper bound for the crossing number of K n ?

Answer & Explanation

yorbakid2477w6

yorbakid2477w6

Beginner2022-10-30Added 12 answers

Step 1
We need to assume the vertices are in "general position."
Step 2
Take any 4 vertices. One pair of chords determined by these vertices meets inside the polygon, the other two do not. So the number of chord intersections inside the polygon is ( n 4 ) .
Josiah Owens

Josiah Owens

Beginner2022-10-31Added 3 answers

Step 1
If you want to approach it using your method of f ( n ) = f ( n 1 ) + something, then observe that when we introduce the additional vertex V, any new point of intersection must involve this vertex V.
Step 2
Any point of intersection will have to involve 3 vertices from the other n 1. It is clear that given any set of 3 vertices, there is a unique point of intersection, obtained by adjoining V to the 'middle' vertex. Hence "something" = ( n 1 3 ) .
Step 3
You can now solve the recurrence to show that f ( n ) = ( n 4 ) .

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