We have circle with radius R and inside it we choose at random 2 points A and B.Find the probability the circle with center A and radius AB to be inside the circle(It is possible both circles to be tangent)

Emmanuel Giles

Emmanuel Giles

Answered question

2022-11-02

Probability circle to be in a circle
We have circle with radius R and inside it we choose at random 2 points A and B.Find the probability the circle with center A and radius AB to be inside the circle(It is possible both circles to be tangent)
What I've concluded : the first point A has range from [0;R] and the second point B must have range from [ 0 ; R O A ] .But how should I find the probability?

Answer & Explanation

Prezrenjes0n

Prezrenjes0n

Beginner2022-11-03Added 19 answers

Step 1
I can propose a little different approach. We want to choose 2 points (call them X,Y) inside a circle of radius R. Due to circle being rotation-invariant, we can always rotate so that X lies on [ 0 , R ] × { 0 } R 2 . So that we need to find the distribution of Z := | | X | | . We have F Z ( t ) = π t 2 π R 2 χ [ 0 , R ] ( t ) + χ ( R , + ) ( t ), so that the density is g Z ( t ) = 2 R 2 t χ [ 0 , R ] ( t ).
Let A F be an event - circle with center X and radius | | Y X | | is inside our circle of radius R.
Step 2
Then we have P ( A | Z ) = π ( R Z ) 2 π R 2 = ( R Z ) 2 R 2
And by total expectation
P ( A ) = E [ P ( A | Z ) ] = 1 R 2 E [ ( R Z ) 2 ] = 1 R 2 0 R ( R z ) 2 z 2 R 2 d z = 2 R 4 0 R s 2 ( R s ) d s = 2 R 4 ( R 4 3 R 4 4 ) = 1 12

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