Consider the region that is between x^2+y^2+z^2=1, x^2+y^2+z^2=9, and finally above the upper nappe of the cone z^2=3(x^2+y^2) upon further consideration, does the smaller sphere even matter? wouldn't it just represent a hole in the larger sphere, an area im not even worried about finding the volume of ?

Rosemary Chase

Rosemary Chase

Answered question

2022-11-10

The volume of the region between two spheres and the upper nappe of a cone
I am really having trouble constraining the region between these three surfaces. I am imagining a sort of "Dome", or a "muffin head" sort of shape. Is this correct ? Anyway, I need to be able to write the following volume integral in rectangular, cylindrical and spherical coordinates:
Consider the region that is between x 2 + y 2 + z 2 = 1, x 2 + y 2 + z 2 = 9, and finally above the upper nappe of the cone z 2 = 3 ( x 2 + y 2 ).
Upon further consideration, does the smaller sphere even matter?

Answer & Explanation

Jackson Trevino

Jackson Trevino

Beginner2022-11-11Added 14 answers

Step 1
First find where the cone intersects the inner sphere:
x 2 + y 2 = 1 z 2
z 2 = 3 3 z 2
z 2 = 3 4
Step 2
This means that the radius of the boundary between the cone and inner sphere is 1 2 , and the radius of the boundary between the cone and the radius of the boundary for the outer sphere can be found to be 33 2 , using the same process. Converting the sphere equations into cylindrical coordinates and using as bounds 0 θ < 2 π and 1 2 r < 33 2 , the volume integral is as follows:
V = 0 2 π 1 2 33 2 ( 9 r 2 1 r 2 ) r d r d θ
A similar procedure can be followed to find the integral in rectangular and spherical coordinates.

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