Distance between (3,-1,1) and (2,-3,1)?

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Gilbert Petty · Accepted Answer

let the pts. be A(3,-1,1) &amp;amp; B(2,-3,1). So, By distance formula      A    B    =                            (                                    (                              x                2                            -                              x                1                            )                        2                    )                +                              (                          y              2                        -                          y              1                        )                    2                +                              (                          z              2                        -                          z              1                        )                    2                          A    B    =                                        (            2            -            3            )                    2                +                              (            -            3            +            1            )                    2                +                              (            1            -            1            )                    2                          A    B    =                  1        +        4        +        0                  A    B    =          5

Distance between (3,-1,1) and (2,-3,1)?

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