Question: "A flowerpot accidentally falls off the window of..."

Answered question

2021-10-18

A flowerpot accidentally falls off the window of a condominium unit. Your unit is located below where the flowerpot had fallen. Your window measures to be 1.60 m tall, and the time it takes the flowerpot to move past your window is 0.150 s (from the top part to the bottom part of the window). How high from the top of your window did the flowerpot fell off?

Answer & Explanation

Jeffrey Jordon

Expert2021-10-26Added 2605 answers

$Y = Y_{o} + V Y_{o} t + (\frac{1}{2}) a t^{2}$

$1.6 = 0 + V_{i} (0.150) + \frac{1}{2} (9.8) ({0.150}^{2})$

Do the algebra and solve for $V_{i}$

$9.9316$ m/s = $V_{i}$

We can use the velocity squared equation to find the distance $H$ the question asks for using this $V_{i}$ we found. Here I do use the origin I established in the beginning.

$V^{2} = V_{o}^{2} + 2 a (Y - Y_{o})$

$({9.9316}^{2}) = 0^{2} + 2 (9.8) (H - 0)$

Do the algebra and solve for $H$

$H = 5.03$ m

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